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3x^2=1/100
We move all terms to the left:
3x^2-(1/100)=0
We add all the numbers together, and all the variables
3x^2-(+1/100)=0
We get rid of parentheses
3x^2-1/100=0
We multiply all the terms by the denominator
3x^2*100-1=0
Wy multiply elements
300x^2-1=0
a = 300; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·300·(-1)
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{3}}{2*300}=\frac{0-20\sqrt{3}}{600} =-\frac{20\sqrt{3}}{600} =-\frac{\sqrt{3}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{3}}{2*300}=\frac{0+20\sqrt{3}}{600} =\frac{20\sqrt{3}}{600} =\frac{\sqrt{3}}{30} $
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